What's the output?

Question

```javascript
async function* range(start, end) {
  for (let i = start; i <= end; i++) {
    yield Promise.resolve(i);
  }
}

(async () => {
  const gen = range(1, 3);
  for await (const item of gen) {
    console.log(item);
  }
})();
```

Accepted Answer

The generator function `range` returns an async object with promises for each item in the range we pass: `Promise{1}`, `Promise{2}`, `Promise{3}`. We set the variable `gen` equal to the async object, after which we loop over it using a `for await ... of` loop. We set the variable `item` equal to the returned Promise values: first `Promise{1}`, then `Promise{2}`, then `Promise{3}`. Since we're _awaiting_ the value of `item`, the resolved promise, the resolved _values_ of the promises get returned: `1`, `2`, then `3`.

関連概念

What's the output?

What will happen?

What's missing?

関連概念

関連概念

What's the output?

What will happen?

What's missing?

関連概念